(y^3/x^2)-5

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Solution for (y^3/x^2)-5 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(y^3)/(x^2)-5 = 0

x^-2*y^3 = 5 // : y^3

x^-2 = 5/(y^3)

-2 < 0

1/(x^2) = 5/(y^3) // * x^2

1 = x^2*(5/(y^3)) // : 5/(y^3)

1/(5/(y^3)) = x^2

x^2 = 1/(5/(y^3)) // ^ 1/2

abs(x) = 1/((5^(1/2))/(y^(3/2)))

x = 1/((5^(1/2))/(y^(3/2))) or x = -(1/((5^(1/2))/(y^(3/2))))

x in { 1/((5^(1/2))/(y^(3/2))), -(1/((5^(1/2))/(y^(3/2)))) }

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